The gravitational force between two particles of masses `m_(1)` and `m_(2)` separeted by the same distance, then the gravitational force between them

Correct option is: (A) F

 C)\(\sqrt{\cfrac{GM}{4r}}\)

Correct option is C) equal

D) F2 = 16F1

B) force of attraction

By Universal law of gravitation, F = \(\frac{Gm_1m_2}{r^2}\) The force acting between two point masses m1 and m2, is independent of the nature of medium between them. Therefore, Gravitational force acting between two...

Answer is (A) \(\frac{r_2}{r_1}\)  F =   \(\frac{mv^2}{r}\) If m and v are constants, then F ∝ \(\frac{1}{r}\) ∴ \(\frac{F_1}{F_2}\) = \(\Big(\frac{r_2}{r_1}\Big)\)

Correct Answer - B distance of null point,`x=d/(sqrt((m_(2))/(m_(1)))+1)` from `m_(1)`, smaller mass

Correct Answer - A `m_(1)r_(1)=m_(2)r_(2)`

Correct Answer - D They cannot be replaced by point masses if they are kept inside one another.