The force exerted by an electric field on a charge of +10 µC at a point is 16 × 10-4 N. What is the intensity of the electric field at the point?
Answered Feb 05, 2023
Given: q = 10 µC = 10 × 10-6 C, F = 16 × 10-4 N
To find: Electric field intensity (E)
Formula: E = \(\frac{F}{q}\)
Calculation: From formula,
E = \(\frac{16\times10^{-4}}{10\times10^{-6}}\) = 160 N/C
Correct option is A) qvB
(B) energy is used from some outside source
Correct option is: (D) 1000 V
Correct option is: (A) 1500 NC-1
Correct option is: (A) 1.39 × 10-11 C
Correct option is: (D) 2 µC
(B) radially outward, radially inward
Correct option is: (B) pE sinθ
Correct option is B) 8N
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