If a charge is moved against the Coulomb force of an electric field,
(A) work is done by the electric field
(B) energy is used from some outside source
(C) the strength of the field is decreased
(D) the energy of the system is decreased
1 Answers
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‘Service’ refers A) Nature of work done B) Amount of work done C) Cost of work done D) No livelihood earned
A) Nature of work done
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If a charge q is moving against an electric force Fe through a distance “d” between the terminals of a battery then the em/is ……………………..
Correct option is C)Fed/q
2 Answers 3 views
A charge is moved from a point A to point B. The work done to move an unit charge during this process is called ……………………
C) potential difference between A and B
2 Answers 1 views
State and explain Coulomb’s law of electric charge in scalar form.
Coulomb’s law: The force of attraction or repulsion between two point charges at rest is directly proportional to the product of the magnitude of the charges and inversely proportional to the...
2 Answers 2 views
Give conversions of micro-coulomb, nanocoulomb and pico-coulomb to coulomb.
1 microcoulomb (µC) = 10-6 C 1 nanocoulomb (nC) = 10-9 C 1 picocoulomb (pC) = 10-12 C
2 Answers 1 views
Charge on an electron is 1.6 × 10^-19 C. How many electrons are required to accumulate a charge of one coulomb?
1 electron = 1.6 × 10-19 C ∴ 1 C = \(\frac{1}{1.6\times10^{-19}}\) electrons = 0.625 × 1019 electrons ……. (Taking reciprocal from log table) = 6.25 × 1018 electrons Hence, 6.25 × 1018 electrons are required to accumulate a charge of...
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The force exerted by an electric field on a charge of +10 µC at a point is 16 × 10^-4 N. What is the intensity of the electric field at the point?
Given: q = 10 µC = 10 × 10-6 C, F = 16 × 10-4 N To find: Electric field intensity (E) Formula: E = \(\frac{F}{q}\) Calculation: From formula, E = \(\frac{16\times10^{-4}}{10\times10^{-6}}\) = 160 N/C
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Find the work done when a point charge of 2.0 pc is moved from a point at a potential of -10 V to a point at which the potential is zero.
VA = -10V, VB = 0, q = 2 × 10-6 C To Find: Work done (W) Formula: VBA = \(\frac{W}{q}\) Calculation: From formula, W = VBA × q = (VB – VA) × q = (0 + 10) × 2 × 10-6 = 20 ×...
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Four coulomb charge is uniformly distributed on 2 km long wire. Its linear charge density is
Correct option is: (D) 2 × 10-3 C/m
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A particle of charge `16xx10^(-18)` coulomb moving with velocity `10m//s` along the `x-` axis enters a region where a magnetic field of induction B is
Correct Answer - 1 `V=(E)/(B)`
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