If two coins are tossed then the chance(probability) of getting 2 heads is

A) 3/4

B) 1/4

C) 1/2

D) None


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Correct option is (B) 1/4

If two coins are tossed then possible outcomes are S = {HH, HT, TH, TT}

Let event E = Getting two heads = {HH}

\(\therefore\) n(E) = 1 & n(S) = 4

\(\therefore\) P(E) \(=\frac{n(E)}{n(S)}=\frac14\)

Hence, the probability of getting 2 heads is \(\frac{1}{4}.\)