Correct option is (B) 1/4
If two coins are tossed then possible outcomes are S = {HH, HT, TH, TT}
Let event E = Getting two heads = {HH}
\(\therefore\) n(E) = 1 & n(S) = 4
\(\therefore\) P(E) \(=\frac{n(E)}{n(S)}=\frac14\)
Hence, the probability of getting 2 heads is \(\frac{1}{4}.\)