let length of the rectangle be L and breadth be B
so by the problem perimeter 2(IL+B)=34
=> L+B =17 .......(1)
=> L2+B2+2LB=289 ..........(2)
and the square of the diagonal = L2+B2=132 =169 .....(.3)
By...
Correct option is (C) 448 cm2
Surface area of cuboid \(=2\,(lb+bh+hl)\)
\(=2\,(10\times8+8\times8+8\times10)\)
\(=2\,(80+64+80)\)
\(=2\times224=448\,cm^2\)