Three cubes each of volume 64 cm^3 are joined end to end to form a cuboid. Find the total surface area of the cuboid so formed?

Correct Answer - (i) `432 cm^(3), 180 cm^(2), 372 cm^(2)` (ii) `2366 m^(3), 520m^(2), 1248 m^(2)` (iii) `45 m^(3), 21 m^(2), 201 m^(2)` (iv) `36m^(3), 291 m^(2), 303 m^(2)`

Correct Answer - `269.5 cm^(3)`

Correct Answer - `1078 cm^(3)`

Correct option is (C) 448 cm2 Surface area of cuboid \(=2\,(lb+bh+hl)\) \(=2\,(10\times8+8\times8+8\times10)\) \(=2\,(80+64+80)\) \(=2\times224=448\,cm^2\)

Correct option is (D) 16 Let \(l,b\;and\;h\) are length, breadth and height of the original cuboid. After increasing each dimension of cuboid by 4 times, length of formed cuboid \(=4\,l,\) breadth of formed cuboid = 4b and height of formed...

1. B) 405 cm3 2. C) 405 cm2 3. D) 8 4. D) 4 : 9

Correct Answer - B Volume of new cube formed `= (3^(3) + 4^(3) + 5^(3)) cm^(3)` `= (27 + 64 + 125) cm^(3) = 216 cm^(3)` Let `a^(3) = 216 =...

Correct Answer - C Volume of big cube = Sum of the volumes of smaller cubes.