If each dimension of a cuboid is increased by 4 times, then the total surface area becomes …………….. times the original area. 

Correct Answer - (i) `432 cm^(3), 180 cm^(2), 372 cm^(2)` (ii) `2366 m^(3), 520m^(2), 1248 m^(2)` (iii) `45 m^(3), 21 m^(2), 201 m^(2)` (iv) `36m^(3), 291 m^(2), 303 m^(2)`

Correct Answer - `269.5 cm^(3)`

Correct Answer - `1078 cm^(3)`

Correct Answer - 34, 70

Let l be the side of the cube and L, B, H be the dimensions of the cuboid Since l3 = 64 cm3 ∴ l = 4 cm Total surface area of cuboid is...

Given that \(\vec a, \vec b\) and \(\vec c\)are unit vectors. i.e., |\(\vec a\)| = |\(\vec b\)|  = |\(\vec c\)| = 1 And \(\vec a\) + \(\vec b\) + \(\vec c\) = \(\vec 0\) Then \((\vec a+\vec b+\vec c).(\vec a+\vec b+\vec c)=\vec 0.\vec...

Correct option is (A) T.S.A. of the box will become 4 times of original area. Let \(l,b\;and\;h\) are parameters of original box. \(\therefore\) \(2l,2b\;and\;2h\) are parameters of new box. \(\therefore\) Total surface area of new box \(=2\,(2l\times2b+2b\times2h+2h\times2l)\) \(=8\,(lb+bh+hl)\) \(=4\times2\,(lb+bh+hl)\) \(=4\times\) Total surface area of original...

1. B) 405 cm3 2. C) 405 cm2 3. D) 8 4. D) 4 : 9