The length of a rectangular park is 17m more than the breadth. If its perimeter is 178 m, then the length is (in mts)

let length of the rectangle be L and breadth be B so by the problem perimeter 2(IL+B)=34 => L+B =17 .......(1) => L2+B2+2LB=289 ..........(2) and the square of the diagonal = L2+B2=132  =169 .....(.3) By...

Correct option is (A) 8 + 5√2 Area of park \(=(3+\sqrt{2})(2+\sqrt{2})\) \(=6+3\sqrt{2}+2\sqrt{2}+2\) = \(8+5\sqrt{2}\)

Correct option is (C) 3 Area of rectangular sheet \(=(\sqrt{5}+\sqrt{2})(\sqrt{5}-\sqrt{2})\) \(=(\sqrt{5})^2-(\sqrt{2})^2\) = 5 - 2 = 3 square units

Correct option is  A) 8 + 5√2 

Correct option is (C) 48 cm2 \(\therefore\) Curved surface area of formed cylinder = Area of rectangular sheet = 12 \(\times\) 4 \(=48\,cm^2\)

Correct option is (C) 775 Area = \(41\frac{2}{3}\) \(\times\) \(18\frac{3}{5}\) \(=\frac{41\times3+2}3\times\frac{18\times5+3}5\) \(=\frac{123+2}3\times\frac{90+3}5\) \(=\frac{125}3\times\frac{93}5\) \(=25\times31\) \(=775\,m^2.\)

Correct option is  D) 5