The emf of a cell is 12 V. When it sends a current of 1 A through an external resistance, the p.d. across the terminals reduces to 10 V.
The internal resistance of the cell is
(A) 0.1 Ω
(B) 0.5 Ω
(C) 1 Ω
(D) 2 Ω
1 Answers
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The internal resistance of a cell of emf 2 V is 0.1 Ω, it is connected to a resistance of 0.9 Ω. The voltage across the cell will be
Correct answer is (B) 1.8 V
2 Answers 3 views
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2 Answers 1 views
A voltmeter is connected across a battery of emf 12 V and internal resistance of 10 Ω. If the voltmeter resistance is 230 Ω, what reading
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2 Answers 1 views
A cell of emf E and internal resistance r is connected across an external resistance R (R >> r). The p.d. across R is
Correct option is: (B) E(I – \(\frac{r}{R}\))
2 Answers 1 views
Emf of a cell is 2.2 volt. When resistance R = 5 Ω is connected in series, potential drop across the cell becomes 1.8 volt.
Correct option is: (A) 10/9 Ω
2 Answers 1 views
If a battery of emf 2 V with internal resistance one ohm is connected to an external circuit of resistance R across it
Correct option is: (D) 3 Ω
2 Answers 1 views
The internal resistance of a cell of emf 2 V is 0.1 Ω. It is connected to a resistance of 3.9 Ω. The voltage across the cell will be
Correct option is: (C) 1.95 V
2 Answers 1 views
The emf of a cell is `Ev`, and its its internal resistance is `1Omega`. A resistance of `4Omega` is joined to battery in parallel. This is connected i
Correct Answer - C `r=R[(l_(1)-l_(2))/(l_(2))]`
2 Answers 1 views
The pd across terminals of a cell is found to be 29 volt and 28 volt respectively when it delivers a current of 1 ampere and 2 ampere respectively. Th
Correct Answer - B `r=((E-V)/(V))R`
2 Answers 2 views