Emf of a cell is 2.2 volt. When resistance R = 5 Ω is connected in series, potential drop across the cell becomes 1.8 volt. Value of internal resistance of the cell is
Given: E = 12 volt, r = 10 Ω, R = 230 Ω
To find: Reading shown by voltmeter (V)
Formula: i. I = \(\frac{E}{R+r}\)
ii. V = E – Ir
Calculation:
From formula (i),
I = \(\frac{12}{230+10}=\frac{12}{240}=\frac{1}{20}\) A
From...
i. Let n identical cells, each of emf E and internal resistance r, be connected in series. Let the current supplied by this combination to an external resistance R be...