The internal resistance of a cell of emf 2 V is 0.1 Ω, it is connected to a resistance of 0.9 Ω. The voltage across the cell will be
(A) 0.5 V
(B) 1.8 V
(C) 1.95 V
(D) 3V
1 Answers
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A battery of emf 6V internal resistance 5`Omega` is joined in parallel with another cell of emf of 10V and internal resistance `1Omega` and the combin
Correct Answer - `6/11 A through 6-V battery in opposition to its emf and `(1)3/11` A through 10-V battery in direction of the emf
2 Answers 1 views
A battery of emf 6 volts and internal resistance `1Omega` is connected in parallel to another battery of emf 8V and internal resistance `2Omega`. The
Correct Answer - `5/8`A
2 Answers 1 views
An accumulator of emf `2 V` and negligible internal resistance is connected across a uniform wire of length 10 m and resistance `30 Omega` The appropr
Correct Answer - 7.5 m,8.75 m,6.25 m
2 Answers 1 views
A shortage battey with an emf of 10V and an internal resistance `1Omega` is connected across an extenal resistance R and liberates of 9W power. Find t
Correct Answer - 9V or 1V, `0Omega or 1//9Omega`
2 Answers 1 views
vii) A cell of emf \( 1.1 V \) and internal resistance \( r \) is connected across an external resistor of resistance \( R=10 \). The potential difference across the resistor is a) \( 0.1 V \) b) \( 0.9 V \) c) \( 1.0 V \) d) \( 1.1 V \)
Given E = 1.1 V r = r R = 10 r Potential difference across the resistor = IR = (E/R+r) R = (1.1/10r+r) 10 r \(=\frac{1.1\times10\,r}{11\,r\times10}\) = 11/11 = 1 volt option (c) is correct.
2 Answers 2 views
A battery of emf 2 V and internal resistance `0.5 Omega` is connected across a resistance of `9.5 Omega`. How many electrons pass through a cross-sect
Correct Answer - `1.25xx10^(18)`
2 Answers 1 views
A voltmeter is connected across a battery of emf 12 V and internal resistance of 10 Ω. If the voltmeter resistance is 230 Ω, what reading
Given: E = 12 volt, r = 10 Ω, R = 230 Ω To find: Reading shown by voltmeter (V) Formula: i. I = \(\frac{E}{R+r}\) ii. V = E – Ir Calculation: From formula (i), I = \(\frac{12}{230+10}=\frac{12}{240}=\frac{1}{20}\) A From...
2 Answers 1 views
A cell of emf E and internal resistance r is connected across an external resistance R (R >> r). The p.d. across R is
Correct option is: (B) E(I – \(\frac{r}{R}\))
2 Answers 1 views
If a battery of emf 2 V with internal resistance one ohm is connected to an external circuit of resistance R across it
Correct option is: (D) 3 Ω
2 Answers 1 views
The internal resistance of a cell of emf 2 V is 0.1 Ω. It is connected to a resistance of 3.9 Ω. The voltage across the cell will be
Correct option is: (C) 1.95 V
2 Answers 1 views