vii) A cell of emf \( 1.1 V \) and internal resistance \( r \) is connected across an external resistor of resistance \( R=10 \). The potential difference across the resistor is a) \( 0.1 V \) b) \( 0.9 V \) c) \( 1.0 V \) d) \( 1.1 V \)


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Given E = 1.1 V

r = r

R = 10 r

Potential difference across the resistor = IR

= (E/R+r) R

= (1.1/10r+r) 10 r

\(=\frac{1.1\times10\,r}{11\,r\times10}\)

= 11/11

= 1 volt

option (c) is correct.

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