A body is projected vertically up from ground with a speed \(\sqrt{gh}\). The average speed of total motion is
A) \(\sqrt{\cfrac{gh}{2}}\)
B) \({\cfrac{\sqrt{gh}}{2}}\)
C) \(\sqrt{2gh}\)
D) none
1 Answers
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A man travels two-third part of his total distance with speed `v_(1)` and rest one-third part with speed `v_(2)`. Find out the average speed of the ma
Correct Answer - `(3v_(1)v_(2))/(v_(2)+2v_(1))
2 Answers 1 views
A body projected vertically upwards, reaches a height of 180 m. Find out `[g=10ms^(-2)]` (i) intial velocity of body (ii) time taken by body to reach
Correct Answer - (i)`60m//s` (ii) 6 sec (iii) 12 sec (iv )160 m (v)`-20m//s` (vi) 2 sec, 10 sec (vii) 6 sec
2 Answers 1 views
A particle when projected vertically upwards from the ground, takes time T to reach maximum height H. Find out (i) The height of the particle from gro
Correct Answer - (i) `3H//4,8H//9,8H//9,15H//16, 1:3,1:8,1:8,1:15` (ii) 1 : 7
2 Answers 3 views
A ball is projected from ground in such a way that after 10 seconds of projection it lands on ground 500 m away from the point of projection. Find out
Correct Answer - (i)`theta=45^(@)` (ii)`50sqrt(2)m//s` (iii)`50m//sec`
2 Answers 10 views
A body is projected from ground with velocity u making an angle `theta` with horizontal. Horizontal range of body is four time to maximum height attai
Correct Answer - (i)`theta=45^(@)` (ii)`R=(u^(2))/(g),H=(u^(2))/(4g)` (iii) 1 : 1
2 Answers 1 views
A tower stands vertically on the ground. From a point on the ground, 20m away from the foot of the tower, the angle of elevation of the top of the tow
Correct Answer - `34.64 m`
2 Answers 1 views
A body projected vertically with a velocity ‘u’ from ground. Its velocity
C) at \(\cfrac{1}3^{rd}\) of maximum height is \(\sqrt{\cfrac{2}{3}}\) u
2 Answers 1 views
For a vertically projected body, a = A) + g B) g^2
Correct option is C) – g
2 Answers 1 views
A body is projected vertically up. The distance covered in its last second of upward motion if g = 10^2 m/s is
Correct option is C) 5 m
2 Answers 1 views
The time taken, by the body projected vertically up with a speed of 20 m/s to return back to the ground is (g = 10 m/s^2)
Correct option is A) 4 sec
2 Answers 1 views