A ball is projected from ground in such a way that after 10 seconds of projection it lands on ground 500 m away from the point of projection. Find out :-
(i) angle of projection
(ii) velocity of projection
(iii) Velocity of ball after 5 seconds


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Correct Answer - (i)`theta=45^(@)`
(ii)`50sqrt(2)m//s`
(iii)`50m//sec`

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