A ball is projected in a manner such that its horizontal gange is n times of the maximum height. Then find out the ratio of potential energy to kinetic energy at maximum height.
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The range of projectile is 1 .5 km when it is projected at an angle of 15° with horizontal. What will be its range when it is projected at an angle
Correct Option is (C) 3 km We knoe that , range of projectile \(R = \frac{u^2 sin \ 2 \ \theta}{g}\) \(1.5 = \frac{u^2 sin(2 \times 15)}{g}\) \(1.5 = \frac{u^2}{2g}\) \(\frac{u^2}{g} = 3\) when, \(\theta = 45^\circ\) \(R...
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The range of projectile is 1 .5 km when it is projected at an angle of 15° with horizontal. What will be its range when it is projected at an angle
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Two balls are projected at an angle θ and (90° – θ) to the horizontal with the same speed. The ratio of their maximum vertical heights is
Correct Option is (D) \(tan^2 \theta : 1\) Maximum vertical height \(H = \frac{u^2 sin^2 \theta}{g}\) \(H_1 = \frac{u^2 sin^2 \theta}{g}\) \(H_2 = \frac{u^2 sin^2 (90 - \theta)}{g}\) .... \(\because \theta...
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Two balls are projected at an angle θ and (90° – θ) to the horizontal with the same speed. The ratio of their maximum vertical heights is
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A particle when projected vertically upwards from the ground, takes time T to reach maximum height H. Find out (i) The height of the particle from gro
Correct Answer - (i) `3H//4,8H//9,8H//9,15H//16, 1:3,1:8,1:8,1:15` (ii) 1 : 7
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A ball is projected from ground in such a way that after 10 seconds of projection it lands on ground 500 m away from the point of projection. Find out
Correct Answer - (i)`theta=45^(@)` (ii)`50sqrt(2)m//s` (iii)`50m//sec`
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A body is projected at an angle of `45^(@)` with horizontal with velocity of `40sqrt(2)m//s`. Find out (i) Maximum height attained by body (ii) Time o
Correct Answer - (i) 80 m (ii) 8 sec (iii) 320 m (iv) 40 m/s (v) 1 : 1 (vi)`y=x-(x^(2))/(320)m` (vii) 80 m (viii) 60 m
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A body is projected from ground with velocity u making an angle `theta` with horizontal. Horizontal range of body is four time to maximum height attai
Correct Answer - (i)`theta=45^(@)` (ii)`R=(u^(2))/(g),H=(u^(2))/(4g)` (iii) 1 : 1
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20. A coconut of mass \( 2 Kg \) is falling from a coconut free of height \( 10 m \). Find the potential energy, kinetic energy and total energy at the following points. \( \left( g =10 m / s ^{2}\right) \) a) Before falling from the coconut tree. b) Just before hilting the ground. c) At a height \( 4 m \) from the ground. d) Which law is evident from this example?
(a) Given m = 2 kg h = 10 m Potential energy at before falling from the coconut tree. u = mgh u = 2 x 10 x 10 u = 200 joule Kinetic energy will...
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Let \( \vec{a}, \vec{b}, \vec{c} \) be unit vectors such that \( \vec{a}+\vec{b}+\vec{c}=\overrightarrow{0} \). Which one of the following is correct ? [IIT-2007] (a) \( \vec{a} \times \vec{b}=\vec{b} \times \vec{c}=\vec{c} \times \vec{a}=\overrightarrow{0} \) (b) \( \overrightarrow{ a } \times \overrightarrow{ b }=\overrightarrow{ b } \times \overrightarrow{ c }=\overrightarrow{ c } \times \overrightarrow{ a } \neq \overrightarrow{0} \) (c) \( \overrightarrow{ a } \times \overrightarrow{ b }=\overrightarrow{ b } \times \overrightarrow{ c }=\overrightarrow{ a } \times \overrightarrow{ c } \neq \overrightarrow{0} \) (d) \( \vec{a} \times \vec{b}, \vec{b} \times \vec{c}, \vec{c} \times \vec{a} \) are mutually \( \perp \)
Given that \(\vec a, \vec b\) and \(\vec c\)are unit vectors. i.e., |\(\vec a\)| = |\(\vec b\)| = |\(\vec c\)| = 1 And \(\vec a\) + \(\vec b\) + \(\vec c\) = \(\vec 0\) Then \((\vec a+\vec b+\vec c).(\vec a+\vec b+\vec c)=\vec 0.\vec...
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