The height (in meters) at any time t (in seconds) of a ball thrown vertically varies according to equation `h(t)=-16t^(2)+256t`. How long after in seconds the ball reaches the hightest point
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Talk Doctor Online in Bissoy App
`d/(dx)sqrt((1-sin2x)/(1+sin2x))i se q u a lto,(0<x<pi/2),` `sec^2x` (b) `-sec^2(pi/4-x)` `sec^2(pi/4+x)` (d) `sec^2(pi/4-x)`
`y=sqrt((1-sin 2x)/(1+ sin 2x))=(cos x - sin x)/(cos x + sin x)=(1-tan x)/(1+ tan x)=tan ((pi)/(4)-x)` `therefore (dy)/(dx)=-sec^(2)((pi)/(4)-x)`
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A stone is thrown vertically upwards from the ground with a velocity 15 m/s. At the same instant a ball is dropped from a point directly
Let the stone and the ball meet after time t0. From second equation of motion, the distances travelled by the stone and the ball in that time is given as, Sstone = 15 t0 – \(\frac{1}{2}\) gt02 Sball = \(\frac{1}{2}\) gt02 When...
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A man standing between 2 parallel eliffs fires a gun. He hearns two echos one after 3 seconds and other after 5 seconds.
distance (s) = 1360 m, time for first echo = 3 s, time for second echo = 5 s To Find : speed of sound (v) Formula : speed = distance/time Calculation : Time for first...
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A particle is projected vertically upwards from the earth. It crosses the same point at t=2 sec and t=8 sec. Find out `[g=10 ms^(-2)]` (i) the time fo
Correct Answer - (i) 10 sec (ii) 50 m//s (iii) 125 m (iv) 80 m
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A particle when projected vertically upwards from the ground, takes time T to reach maximum height H. Find out (i) The height of the particle from gro
Correct Answer - (i) `3H//4,8H//9,8H//9,15H//16, 1:3,1:8,1:8,1:15` (ii) 1 : 7
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A ball is thrown from a comer of room of length 20 m and height 5 m such that the ball moves along the length of room just touching the ceiling and dr
Correct Answer - (i)`45^(@)` (ii)`10sqrt(2)m//s` (iii) 2 sec
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A ball of mass 2 kg is moving with velocity 20 m/sec strikes with the surface and rebounds with same speed, if time of contact is 0.1 sec then calcula
Correct Answer - 800 N
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A ball is thrown vertically upwards with velocity 10 m/s from a trolley moving horizontally with velocity of 8 m/s.
Vertical velocity of ball uy=v1 Horizontal velocity of ball ux=v2 Horizontal range of projectile R=2uxuy/g ⟹ R= 2v1v2/g = 2* 10*8/ 10= 16 m
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A ball is thrown vertically upwards with velocity 10 m/s from a trolley moving horizontally with velocity of 8 m/s.
2 Answers
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A ball is thrown upwards with 10 m/s velocity after 1 sec, what is its height?
Correct option is B) 5 m
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