A ball of mass 2 kg is moving with velocity 20 m/sec strikes with the surface and rebounds with same speed, if time of contact is 0.1 sec then calculate average force on the ball.
Given: vA = 10 m/s, vB = 6 m/s,
To find: (i) Velocity of A relative to B (vA – vB)
(ii) Velocity of B relative to A (vB – vA)
Formulae: (i) vAB = vA – vB
(ii) vBA =...
Given: m1 = 10 kg, m2 = 4 kg
u1 = 5 m/s, u2 = 2 m/s, e = \(\frac{1}{2}\)
To find: Velocity after impact (v1 and v2)
Formulae:
i. m1u1 + m2u2 = m1v1 + m2v2
ii. e = \((\frac{v_2-v_1}{u_1-u_2})\)
Calculation:
From formula (i),
10 × 5...
Given: m = 0.1 kg, u = 20 m/s, t = 0.1 s
To find: Impulse (J), Average force (F)
Formulae:
i. J = mv – mu
ii. F = \(m\frac{(v-u)}{t}\)
Calculation:
From formula (i).
J = m(v...
m = 0.150 kg, v = 20 m/s,
u = -12 m/s and t = 0.01 s
To find: Average force (F)
Formula: F = \(\frac{m(v-u)}{t}\)
Calculation: From formula,
F = \(\frac{0.150[20-(-12)]}{0.01}\) = 480 N
The average force exerted...
Correct Option is: (A) 2 mv
Initial velocity of body before collision u = v
then initial momentum Pi = - MV
final velocioty of the body \(P_f = MV\)
Change in momentum
\(\Delta P =...