A jet is releasing water at the rate of 6 kg/see with speed of 4 m/sec. Now this water strikes a block of mass 10 kg. find the force exerted on block

`y=sqrt((1-sin 2x)/(1+ sin 2x))=(cos x - sin x)/(cos x + sin x)=(1-tan x)/(1+ tan x)=tan ((pi)/(4)-x)` `therefore (dy)/(dx)=-sec^(2)((pi)/(4)-x)`

Correct Answer - `198.77` MeV

Correct Answer - `(a) 2 cm//sec (b) 4 cm^(2)//sec`,Increase

Correc Option is (D) 900 \(kmh^{-1}\) \(v_p = -500\) km/h \(V_{gp} = 1400\) km/h The speed of burnt gas with respect to the jet airplane is \(\overrightarrow v_{gp} = \overrightarrow v_g - \overrightarrow v_p\) \(1400 = v_g +...

Correct Answer - `a=(10)/(19)m//s^(2)`

Correct Answer - 800 N

Correct Answer - `a=2.4 m//s^(2)`

Correct option is B) 8N