​ If √10 = 3.162, then  √40 = ?

Correct Answer - (a) 0.2 सेमी`" "`(b) 3.0 सेमी `" "` (c )11.6 सेमी `" "` (d) 11.6 सेमी (e) 16.2 सेमी `" "(f) 8.3 सेमी

Focal length of spherical mirrors are independent of the medium.

t18=t1+17×d t14=t1 +13×d solving the two equtaions, t18-t14= 4d subtisting 4d=32 =  d=8

Correct option is (C) 0.3162 \(\because\) \(\sqrt{10}=3.162\) \(\therefore\) \(\frac1{\sqrt{10}}=\frac{\sqrt{10}}{\sqrt{10}\times\sqrt{10}}=\frac{\sqrt{10}}{10}\) \(=\frac{3.162}{10}=0.3162\)

Correct option is (A) ΔABC ≅ ΔDEF In \(\triangle ABC\;and\;\triangle EFD,\) AB = EF   (Both hypotenuse are equal) \(\angle C=\angle D\) \(=90^\circ\)   (Angles opposite to hypotenuse) AC = ED         (Given) \(\therefore\) \(\triangle ABC\cong\triangle EFD\)   ...

12011 + 22011 + 32011 +...... +20102011 = (12011 + 20102011) + (22011 + 20092011) + (32011 + 20082011) ...... (10112011 + 10002011) These terms are of the form an + bn, so they will be divided by a + b, as n...

Correct option is (D) ₹ 680 Let cost price of radio be Rs x. \(\therefore\) Selling price = x + 10% of x = x + \(\frac{10x}{100}\) = x + \(\frac{x}{10}\) \(=\frac{11x}{10}.\) Given that selling price = Rs 748 \(\therefore\) \(\frac{11x}{10}=748\) \(\Rightarrow\) \(x=\frac{748}{11}\times10=680\) \(\therefore\) Cost price...