A body released from height ‘h’ takes time’t’ to reach the ground. After time t/2, its height from the ground is
A) \(\cfrac{h}2\)
B) \(\cfrac{h}4\)
C) \(\cfrac{3h}4\)
D) \(\cfrac{h}3\)
Answered Feb 05, 2023
Correct Answer - 960 `cm^(3)`
Correct Answer - (i)`60m//s` (ii) 6 sec (iii) 12 sec (iv )160 m (v)`-20m//s` (vi) 2 sec, 10 sec (vii) 6 sec
Correct Answer - (i) `3H//4,8H//9,8H//9,15H//16, 1:3,1:8,1:8,1:15` (ii) 1 : 7
Correct Answer - (i)`theta=45^(@)` (ii)`R=(u^(2))/(g),H=(u^(2))/(4g)` (iii) 1 : 1
(a) Given m = 2 kg h = 10 m Potential energy at before falling from the coconut tree. u = mgh u = 2 x 10 x 10 u = 200 joule Kinetic energy will...
B) height of the tower
Correct option is B) 2g
a. Male gamete (sperm) travels in the female reproductive tract after being released. The path which it takes to fertilise the female gamete (egg) is vagina uterus fallopian tube resulting in...
B) if there were no air resistance
Correct Answer - B `t=sqrt((2H)/g)`
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