A projectile is thrown at angle `beta` with vertical.It reaches a maximum height `H`.The time taken to reach the hightest point of its path is

C) A + d = i1 + i2 

 C) \(\cfrac{3h}4\)

B) height of the tower

A) average velocity

Correct option is (B) 30° Let the angle be x. Then its complementary angle is 2x. \(\therefore\) x+2x = \(90^\circ\) \(\Rightarrow\) 3x = \(90^\circ\) \(\Rightarrow\) x = \(\frac{90^\circ}3=30^\circ\) Hence, the required angle is \(30^\circ.\)

B) if there were no air resistance

Correct option is (D) 3 Distance covered by car by travelling 60 kmph in 4 hours = speed \(\times\) time \(=60\times4\) = 240 km When car travels at 80 kmph then time by the car \(=\frac{Distance}{Speed}\) \(=\frac{240}{80}\) =...

Correct Answer - [No]

Correct Answer - C `Deltat=(2u)/(g)`