Given: q = 10 µC = 10 × 10-6 C, F = 16 × 10-4 N
To find: Electric field intensity (E)
Formula: E = \(\frac{F}{q}\)
Calculation: From formula,
E = \(\frac{16\times10^{-4}}{10\times10^{-6}}\) = 160 N/C
Given: q = 5C, r = 1 m
To find: Flux (ø)
Formulae: i. E = \(\frac{1}{4\pi \epsilon_0}\times\frac{q}{r^2}\)
ii. ø = E × A = E (4πr2)
Calculation: From formula (i),
E = 9 × 109 × \(\frac{5}{1^2}\)
=...