Electrical resistance of a conductor was first determined by
A) Coloumb
B) Faraday
C) George simon Ohm
D) Ampere
We know that R = ρl/A R ∝ l R1/R2 = l1/l2 Given ∵ l2 = 2l1 R1 = 0.60 hm R2/R1 = l2/l1 R2/R1 = 2l1/l1 R2 = 2 R1 R2 = 2 x 0.60 R2 = 1.2 hm
2 Answers 3 viewsHere the thermometric property P is the resistance. If R is the resistance at 27 °C, Using equation, T = \(\frac{100(P_T-P_1)}{(P_T-P_1)}\) For T = 27 °C, P1 = 95.2 Ω, P2 = 138.6 Ω . ∴ 27 = \(\frac{100(R-95.2)}{(138.6-95.2)}\) ∴...
2 Answers 3 viewsCorrect option is D) zero
2 Answers 1 viewsCorrect option is D) insulator
2 Answers 1 viewsD) a, b, c and d
2 Answers 1 viewsB) increases
2 Answers 1 viewsCorrect option is D) halved
2 Answers 1 views1. Electrical conduction in a conductor is due to mobile charge carriers (electrons). 2. These conduction electrons are free to move inside the volume of the conductor. 3. During their random motion,...
2 Answers 1 viewsGiven: R0 = 2.5 Ω α = 4 × 10-3/°C = 0.004/°C T = 80 °C To find: Resistance at 80 °C (RT) Formula: RT = R0(l + αT) Calculation: From formula, RT = 2.5 [1+ (0.004 × 80)] =...
2 Answers 3 views(A) length of the conductor.
2 Answers 1 views