A resistance thermometer has resistance 95.2 Ω at the ice point and 138.6 Ω at the steam point. What resistance would be obtained if the actual temperature is 27 °C?
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Here the thermometric property P is the resistance.
If R is the resistance at 27 °C,
Using equation,
T = \(\frac{100(P_T-P_1)}{(P_T-P_1)}\)
For T = 27 °C, P1 = 95.2 Ω, P2 = 138.6 Ω .
∴ 27 = \(\frac{100(R-95.2)}{(138.6-95.2)}\)
∴ R = \(\frac{27\times(138.6-95.2)}{100}\) + 95.2
= 11.72 + 95.2
= 106.92Ω
The resistance obtained would be 106.92 Ω.