A copper wire has a resistance of \( 0.6 0hm \). Another copper wire of the same mass as the first one is double in length of the first. Find the resistance of the second wire.


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We know that R = ρl/A

R ∝ l

R1/R2 = l1/l2

Given

∵ l2 = 2l1

R1 = 0.60 hm

R2/R1 = l2/l1

R2/R1 = 2l1/l1

R2 = 2 R1

R2 = 2 x 0.60

R2 = 1.2 hm

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