A block of mass 40 kg resting on a horizontal surface just begins to slide when a horizontal force of 120 N is applied to it.

Monjur Alahi

A block of mass 40 kg resting on a horizontal surface just begins to slide when a horizontal force of 120 N is applied to it. Once the motion starts, It can be maintained by a force of 80 N. Determine the coefficients of static friction and kinetic friction

(g = 9.8 m/s2)


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Salim Ahmed Kawsar

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Given: FL = 120N, Fk = 80N, m = 40 kg, g = 9.8 m/s2

To find:

i. Coefficient of static friction (μS)

ii. Coefficient of kinetic friction (μk)

Formulae:

i. μs = \(\frac{F_L}{N}\)

ii. μk = \(\frac{F_K}{N}\)

Calculation:

From formula (i) we get.

N = mg = 40 × 9.8 = 392 N

∴ μs = \(\frac{F_L}{N}=\frac{120}{392}\) = 0.306

From formula (ii) we get,

∴ μk = \(\frac{F_k}{N}=\frac{80}{392}\) = 0.204

1. The coefficient of static friction is 0.306.

2. The coefficient of kinetic friction is 0.204.

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