A wooden block of 50 kg is at rest on the table. A force of 70 N is required to just slide the block. The coefficient of static friction is
(A) \(\frac{6}{7}\)
(B) \(\frac{5}{7}\)
(C) \(\frac{7}{35}\)
(D) \(\frac{1}{7}\)
1 Answers
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Why force of static friction is known as ‘self-adjusting force?
The force of static friction varies in accordance with applied force. Hence, it is called as self adjusting force.
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What is friction? Define coefficient of static friction and coefficient of kinetic friction.
1. The property which resists the relative motion between two surfaces in contact is called friction. 2. The coefficient of static friction is defined as the ratio of limiting force of...
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A block of mass 37 kg rests on a rough horizontal plane having coefficient of static friction 0.3.
Given: m = 37 kg, µs = 0.3, g = 9.8 m /s2 To find : Limiting force (FL) Formula : FL = µsN = µs mg Calculation: From formula, FL = 0.3 × 37 × 9.8 = 108.8...
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The coefficient of static friction between a block of mass 0.25 kg and a horizontal surface is 0.4. Find the horizontal force applied to it.
Given: μS = 0.4, m = 0.25 kg, g = 9.8 m/s2 To find: Force (FL) Formula: FL = μSN = μS(mg) Calculation: From formula, FL = 0.4 × 0.25 × 9.8 = 0.98 N The horizontal force applied...
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A block of mass 40 kg resting on a horizontal surface just begins to slide when a horizontal force of 120 N is applied to it.
Given: FL = 120N, Fk = 80N, m = 40 kg, g = 9.8 m/s2 To find: i. Coefficient of static friction (μS) ii. Coefficient of kinetic friction (μk) Formulae: i. μs = \(\frac{F_L}{N}\) ii. μk = \(\frac{F_K}{N}\) Calculation: From formula (i) we get. N =...
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A 20 kg metal block is placed on a horizontal surface. The block just begins to slide when horizontal force of 100 N is applied to it.
Given: m = 20 kg, FL = 100 N, μk = 0.4 To find: i. Coefficient of static friction (μS) ii. Minimum force required (Fk) Formulae: i. μs = \(\frac{F_L}{N}=\frac{F_L}{mg}\) ii. μS = \(\frac{F_K}{N}\) Calculation: From formula (i), μs = \(\frac{100}{20\times9.8}\) = 0.5102 From formula (ii), Fk = μkN...
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In case of coefficient of static friction (µs), kinetic friction (µk) and rolling friction (µr), which of the following relation is true
Correct option is: (A) µs > µk > µr
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The friction exerted by moving body is called A) static friction
B) sliding friction
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The friction exerted by fluid is called A) static friction
C) rolling friction
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Choose suitable option for matching. Group-A 1. Static friction 2. Sliding friction
B) 1 – b, 2 – d, 3 – e, 4 – a, 5 – c
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