The sides of a quadrilateral ABCD taken in order are 6 cm, 8 cm, 12 cm and 14 cm respectively and the angle between the first two sides is a right angle. Find its area. (Given, `sqrt(6) = 2.45`.)
Correct answer is (b)
We know that
\(\tau\) = r × F
∵ \(\tau\) \(= \frac{dL}{dt},\) \(F = \frac{dP}{dt}\)
\(\left(\frac{dL}{dt}\right) = r \times \left(\frac{dP}{dt}\right)\)
\(\left(\frac{dL}{dt}\right) - r \times \left(\frac{dP}{dt}\right) = 0\)
Correct option is (B) 135°
ABCD is a cyclic quadrilateral.
\(\angle A\;\&\;\angle C\) are opposite angles in cyclic quadrilateral ABCD
\(\therefore\) \(\angle A+\angle C\) \(=180^\circ\) \((\because\) Sum of opposite angles in a cyclic quadrilateral is \(180^\circ)\)
\(\Rightarrow\) \(\angle C\) \(=180^\circ-\angle A\)
\(=180^\circ-45^\circ\) ...
Correct option is (C) 160°
\(\because\) Sum of all angles in a quadrilateral is \(360^\circ.\)
\(\therefore\) In quadrilateral ABCD,
\(\angle A+\angle B\) \(+\angle C+\angle D\) \(=360^\circ\)
\(\Rightarrow\) \(200^\circ\) \(+\angle C+\angle D\) \(=360^\circ\) \((\because\angle A+\angle B=200^\circ)\)
\(\Rightarrow\) \(\angle C+\angle D\) \(=360^\circ-200^\circ=160^\circ\)
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