In a Quadrilateral ABCD, ∠A + ∠B = 200° then ∠C + ∠D = ………………
A) 110°
B) 180°
C) 160°
D) 300°
Correct option is (C) 160°
\(\because\) Sum of all angles in a quadrilateral is \(360^\circ.\)
\(\therefore\) In quadrilateral ABCD,
\(\angle A+\angle B\) \(+\angle C+\angle D\) \(=360^\circ\)
\(\Rightarrow\) \(200^\circ\) \(+\angle C+\angle D\) \(=360^\circ\) \((\because\angle A+\angle B=200^\circ)\)
\(\Rightarrow\) \(\angle C+\angle D\) \(=360^\circ-200^\circ=160^\circ\)