In a Quadrilateral ABCD, ∠A + ∠B = 200° then ∠C + ∠D = ……………… 

A) 110° 

B) 180° 

C) 160° 

D) 300°


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Correct option is (C) 160°

\(\because\) Sum of all angles in a quadrilateral is \(360^\circ.\)

\(\therefore\) In quadrilateral ABCD,

\(\angle A+\angle B\) \(+\angle C+\angle D\) \(=360^\circ\)

\(\Rightarrow\) \(200^\circ\) \(+\angle C+\angle D\) \(=360^\circ\)  \((\because\angle A+\angle B=200^\circ)\)

\(\Rightarrow\) \(\angle C+\angle D\) \(=360^\circ-200^\circ=160^\circ\)

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Correct option is  C) 160°

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