The lengths of the two sides of a right triangle containing the right angle differ by `2cm.` If the area of the triangle is `24cm^2.` Find the perimeter of the triangle.
Correct Answer - `120^(@)` Let the sides be `x - d, x, x + d`. Then `s = (3x)/(2), (s -a) = (x)/(2) + d`, `(s-b) = (x)/(2), (s-c) = (x)/(2)...
2 Answers 1 viewsCorrect Answer - C `a = 2b and A - B = 60^(@)` We know that `tan.(A -B)/(2) = (a -b)/(a + b) cot.(C)/(2)` or `tan 30^(@) = (1)/(3) cot.(C)/(2)` or...
2 Answers 1 viewsCorrect Answer - B Let a and b the roots of `x^(2) -7 x + 8 = 0` Then `a + b = 7, ab = 8` Also, `C = 60^(@)`...
2 Answers 1 viewsCorrect Answer - (ii), (iii), (v)
2 Answers 1 viewsCorrect Answer - (i) और (iii)
2 Answers 1 viewsCorrect Answer - `32 sqrt(3) cm^(2)`
2 Answers 1 viewsCorrect Answer - 82.8 `cm^(2)`
2 Answers 1 viewsCorrect Answer - 17 cm, 9 cm
2 Answers 1 viewsCorrect answer is (b) We know that \(\tau\) = r × F ∵ \(\tau\) \(= \frac{dL}{dt},\) \(F = \frac{dP}{dt}\) \(\left(\frac{dL}{dt}\right) = r \times \left(\frac{dP}{dt}\right)\) \(\left(\frac{dL}{dt}\right) - r \times \left(\frac{dP}{dt}\right) = 0\)
2 Answers 1 views