If two sides of a triangle are roots of the equation `x^(2) -7x + 8 = 0` and the angle between these sides is `60^(@)` then the product of inradius and circumradius of the triangle is
A. `(8)/(7)`
B. `(5)/(3)`
C. `(5sqrt2)/(3)`
D. 8
Correct Answer - B
Let a and b the roots of `x^(2) -7 x + 8 = 0`
Then `a + b = 7, ab = 8`
Also, `C = 60^(@)`
`rArr c^(2) = a^(2) + b^(2) - ab`
`rArr c^(2) = (a +b)^(2) -3ab = 49 -24 = 25`
`rArr c = 5`
`:. r.R = (abc)/(2(a+b+c)) = (8xx5)/(2(7+5)) = (5)/(3)`
Correct Answer - A
Since `DeltaABC` is right angled at C, circum-radius, `R = (c)/(2)`
Now, `r = (s -c) tan (C//2) = (s-c) tan (pi//4) = s -c`
Thus, `2(r...
Correct Answer - B
We have
`Delta = (sqrt3)/(4) a^(2), s = (3a)/(2)`
`:. r = (Delta)/(s) = (a)/(2sqrt3), R = (abc)/(4Delta) = (a^(3))/(sqrt3 a^(2)) = (a)/(sqrt3)`
and `r_(1) = (Delta)/(s-a)...