Arrange the following compounds in order of increasing molar conductivity . `(i) K[Co(NH_(3))_(2)(NO_(2))_(4)]" " (ii) [Cr(NH_(3))_(3)(NO_(2))_(3)]` `

`CH_(3)-CH_(2)-CH_(3)ltCH_(3)-CHOltCH_(3)-CH_(2)-OH`

`wedge_(m) = (K("conductivity") xx 1000)/(M)` `= (3.905 xx 10^(-5) xx 1000)/(0.001)` `=39.055 " cm"^(2)"mol"^(-1)` `=(wedge^(c)m)/(wedge^(@)m) = (39.05)/(wedge^(@)m) " " [wedge_(CH_(3)COOH)^(@) = wedge_(CH_(3)COO^(-))^(@) + wedge _(H)^(@)+` `= 349.6 + 6 +0.9`...

Correct Answer - (i)Bond dissociation enthalpy should decrease as the bond distance increases from `F_(2)` to `I_(2)` due to the corresponding increase in the size of the atom as we...

Correct Answer - (i)`HCIOltHCIO_(2)ltHCIO_(3)ltHCIO_(4)` (ii)`HCIOltHCIO_(2)ltHCIO_(3)ltHCIO_(4)` (iii)`F^(-)ltCl^(-)ltBr^(-)ltI^(-)` (iv)`HIltI_(2)ltIclltHIO_(4)` (v)`HOIltHOBrltHOClltHOF` (vi)`I_(2)ltBr_(2)ltCl_(2)ltF_(2)` (vii)`HFltHClltHBrltHI` (On the basis of their bond dissociation energies) (viii)`IltBrltClltF`

Correct Answer - 3 (I,ii, iii)

Correct Answer - `(a) i lt iv lt ii lt iii " " (b) X lt O lt N lt C " " ( c) Br^(-) lt S^(2-) lt NO_(3)^(-)...

Correct Answer - 2(i & v)

Correct Answer - 9(a,b,c,d,e,f,g,h and i)

Propyne > propene > propane

Compounds having cations with higher charge have large lattice enthalpy (higher positive value) than compounds having cations with lower charge. Hence, The correct order is NaCl < CaCl2 < AlCl3.