The conductivity of 0.001 `"mol" L^(-1)` solution of `CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1)`. Calculate its molar conductivity and degree of

Monjur Alahi

The conductivity of 0.001 `"mol" L^(-1)` solution of `CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1)`. Calculate its molar conductivity and degree of dissociation `(alpha)`.
`"Given" lambda^(@) (H^(+)) = 349.6 "S" cm^(2) "mol"^(-1) " and " lambda^(0) (CH_(3)COO^(-)) = 40.9 "S" cm^(2) "mol"^(-1)`
(b) Define electrochemical cell. What happens if external potential applied becomes greater than `E_(cell)^(@)` of electrocemical cell?


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

`wedge_(m) = (K("conductivity") xx 1000)/(M)`
`= (3.905 xx 10^(-5) xx 1000)/(0.001)`
`=39.055 " cm"^(2)"mol"^(-1)`
`=(wedge^(c)m)/(wedge^(@)m) = (39.05)/(wedge^(@)m) " " [wedge_(CH_(3)COOH)^(@) = wedge_(CH_(3)COO^(-))^(@) + wedge _(H)^(@)+`
`= 349.6 + 6 +0.9`
`=390.5 "S"cm^(2)"mol"^(-1)]`
` = (39.5 xx 10)/(390.5 xx 100) = 0.1`
(b) Electrochemical Cell : It is a device to convert chemical energy into electrical energy. It is based upon the redox reaction which is spontaneous. The electrode on which oxidation takes place is called the anode and the electrode, where reduction takes place is called cathode. If, external potential applied becomes greater than `E_(cell)^(@)` of electrochemical cell, then the cell behave as electrolytic cell.

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
calculate the emf of the following cell: `Pt(H_(2)" 1 atm")|CH_(3)CH_(2)COOH(0.15 M) ||0.01 M NH_(4)OH|H_(2)" (1 atm)"Pt` `K_(a)` for `CH_(3)CH_(2)COO

Correct Answer - `-0.4603` volt `[H^(+)]` in `CH_(3)CH_(2)COOH=sqrt(CxxK_(a))=sqrt(0.15xx1.4xx10^(-5))` `=1.449xx10^(-3)` `[OH^(-)]` in `NH_(4)OH=sqrt(C xxK_(b))=sqrt(0.01xx1.8xx10^(-5))=0.4242xx10^(-3)` `[H^(+)]` in `NH_(4)OH=10^(-14)/(0.4242 xx 10^(-3))=2.3573xx10^(-11)` `E_(cell)=0.0591 "log"([H^(+)]_(RHS))/([H^(+)]_(LHS))`

2 Answers 1 views
Consider the reaction: (i). `(CH_(3))_(2)CH-CH_(2)Broverset(C_(2)H_(5)OH)to(CH_(3))_(2)CH-CH_(2)-O-C_(2)H_(5)+HBr` (ii). `(CH_(3))_(2)CH-CH_(2)Brovers

Correct Answer - C It is the correct answer. In case the reaction is to proceed by `S_(N^(1))` mechanism in branched chain alkyl halides, rearrangement of the carbocation is expected in...

2 Answers 1 views
Arrange the following in order of decreasing reactivity towards `S_(N^(2))` reactions: `CH_(3)CH_(2)CH_(2)Cl(I),CH_(3)CH_(2)-CHCl-CH_(3)(II)(CH_(3))_(

Correct Answer - A Towards `S_(N^2)` reaction mechianism, the order of reactivity of alkyl halides is primarygtsecondarygttertiary. The steric hindrance has also adverse effect on the reactivity. In the light of...

2 Answers 1 views
Calculate `pH` of the solution which is `10^(-1)M` in `HCl` & `10^(-3)M` in `CH_(3)COOH[K_(a)=2xx10^(-5)]`.Also calculate `[H^(+)]` form `CH_(3)COOH`.

`underset(C(1-alpha))(CH_(3)COOH)hArr underset(Calpha)(CH_(3)COOH)+underset(10^(-1)+Calpha)(H^(+))` ` t=eq` `H^(+)` ion can be considered completely form `HCl` due to less dissocation of `CH_(3)COOH` (because of common ion effect by `H^(+)` of `HCl,alpha ltlt1)` and its low...

2 Answers 1 views
Which of the following solutions added to 1L of a 0.01 M `CH_(3)COOH` solution will cause no change in the degree of dissociation of `CH_(3)COOH` and

In `0.6 m M HCOOH` solution. `K_(a)=([H^(+)]^(2))/(C-[H^(+)])rArr 8xx10^(-4)=([H^(+)]^(2))/(6xx10^(-4)-[H^(+)])` `:.[H^(+)]=4xx10^(-4)M` so solution in A ,C and D are `ISOHYDRIC`.

2 Answers 1 views
Which of the following is maximum reactive towards Lucas reagent? `CH_(2)=CH-CH_(2)OH,CH_(3)-underset(OH)underset(|)(C)H-CH_(3),CH_(3)-CH_(2)-CH_(2)OH

Correct Answer - `CH_(2)=CHCH_(2)OH`

2 Answers 1 views
What is the correct relationship between the following compounds? `CH_(3)-CH_(2)-undersetunderset(CH_(3))(|)(CH)-CH_(2)-CH_(3),CH_(3)-CH_(2)-CH_(2)-CH

Correct Answer - A Carbon skeleton is different in both compounds.

2 Answers 1 views
Which of the following compound will not give positive test with `NaHCO_(3)`.? `{:("Phenol"",",CH_(3)COOH",",CH_(3)CH_(2)SO_(3)H",",CH_(3)C-=CH",",CH_

Correct Answer - Phenol, `CH_(3)C-=CH, CH_(3)CH_(2)OH, "p-cresol"` Phenol is weaker acid as compare to `H_(2)CO_(3)`.

2 Answers 1 views
Give reactivity order for decarboxylation ? `CH_(3)-CH_(2)-COOH CH_(2)=CH-COOH CH-=C-COOH`

(B) In decarboxylation intermediates are, `underset(I)(CH_(3)-CH_(2)^(O)) underset(II)(CH_(2)=CH^(ɵ))underset(III)(CH-=C^(ɵ))` The stability order of carbanion -IIIgtIIgtI So reactiviy order for acid is- IIIgtIIgtI

2 Answers 2 views
Rearrange the following compounds in the increasing order of their boiling points : `CH_(3)-CHO,CH_(3)-CH_(2)-OH,CH_(3)-CH_(2)-CH_(3)`

`CH_(3)-CH_(2)-CH_(3)ltCH_(3)-CHOltCH_(3)-CH_(2)-OH`

2 Answers 1 views
X