Total number of paramagnetic complexes which are inner orbital complexes : `(i) [Cr(NH_(3))_(6)]Cl_(3) " " (ii)[Co(NH_(3))_(6)](NO_(3))_(2)" " (iii)[N

Monjur Alahi

Total number of paramagnetic complexes which are inner orbital complexes :
`(i) [Cr(NH_(3))_(6)]Cl_(3) " " (ii)[Co(NH_(3))_(6)](NO_(3))_(2)" " (iii)[Ni(NH_(3))_(6)]SO_(4)`
`(iv) K_(2)[PtCl_(6)]. " " (v) [V(H_(2)O)_(6)]SO_(4) " " (vi) [Mn(NH_(3))_(6)]SO_(4)`
`(vii)[Fe(H_(2)O)_(5)(NO)]SO_(4) " " (viii)K_(3)[CuCL_(4)]" " Na_(4)[Fe(CN)_(5)(NOS)]`


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Salim Ahmed Kawsar

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Correct Answer - 2(i & v)

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To find formulae of a compound if we titrate `NH_(3)` in the compound with standardized acid. `Cr(NH_(3))_(x)Cl_(3)(aq)+xHCl(aq)rarrxNH_(4)^(+)(aq)+Cr

20ml 1.5MHCl `rArr 20xx1.5xx10^(-3)=0.03` mol HCl moles of `Cr(NH_(3))_(x)Cl_(3)=("moles of HCl")/(x)` `=(0.03)/(x)` so `(0.03)/(x)=(1.3025)/(55+106.5+17x)` `0.51x +4.845-1.3025x` `4.845=(1.3025-0.51)x` `4.845=0.7925x` `x=(4.845)/(0.7925)=6.11`

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Correct Answer - `[(eB (b^(2) - a^(2)))/(2 mb)]`

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Correct Answer - 3 (I,ii, iii)

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Correct Answer - 3 (iii , v, vi)

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Arrange the following compounds in order of increasing molar conductivity . `(i) K[Co(NH_(3))_(2)(NO_(2))_(4)]" " (ii) [Cr(NH_(3))_(3)(NO_(2))_(3)]` `

Correct Answer - `ii lt i lt iv lt iii`

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Correct Answer - `(a) i lt iv lt ii lt iii " " (b) X lt O lt N lt C " " ( c) Br^(-) lt S^(2-) lt NO_(3)^(-)...

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C) a→ii, b→i, c→iii

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