Correct Answer - Both the lines lie on the same side of point (8,-9)
Given lines are parallel lines.
`"Let "L_(1)(x,y) = 2x+3y-4`
`"and "L_(2)(x,y) = 6x+9y+8`
`" " L_(1)(8,-9) =2(8)+3(-9)+4=-7...
`|{:(1,1,-2),(2,-1,1),(a,b,-c):}| = 0`
or a+5b-3c=0
or `-(a)/(3)-(5)/(3)b+c = 0`
Hence, 2ax+3by+c=0 is concurrent at 2x = -1/3 and 3y=-5/3.
So, x=-1/6, y=-5/9.
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