If A + B = A - B then vector B must be
(A) zero vector
(B) unit vector
(C) Non zero vector
(D) equal to vector A
`[E]=[ML^(2)T^(-2)]=(5)` `=(10)^(2)(5)^(2)=20` joules
2 Answers 2 views`|veca+vecb+vecc+vecd|^(2)=sum|veca|^(2)+2sumveca.vecb=4+2vecd.(veca+vecb+vecc) " " (veca,vecb,vecc "are mutually perpendicular")` `Let vecd=lambdaveca+muvecb+v vecc. Then vecd.veca=vecd.vecb=vecd.vecc=costheta`Therefore, `lambda=mu=v=costheta` ` lambda^(2)+mu^(2)+v^(2)=1Rightarrow3cos^(2)theta=1costheta=1/sqrt3` `|veca+vecb+vecc+vecd|^(2)=4+-(2.3)/sqrt3=4+-2sqrt3`
2 Answers 1 views`Let" " vecr=x_(1)veca+x_(2)vecb+x_(3)veccRightarrow vecr.(vecbxxvecc)=x_(1)veca.(vecbxxvecc)or x_(1)=([vecr vecb vecc])/([veca vecb vecc])`. `Also, " " vecr.(veccxxveca)=x_(2)vecb.(veccxxveca)orx_(2)=([vecrveccveca])/([vecavecbvecc])` `and vecr.(vecaxxvecb)=x_(3)vecc. (vecaxxvecb)or x_(3)=([vecr vecavecb])/([veca vecbvecc])` `Rightarrow vecr=([vecrvecb vecc])/([vecavecbvecc])veca+([vecrveccveca])/([vecavecbvecc])vecb+([vecrvecavecb])/([vecavecb vecc])vecc` `or [vecbveccvecr]veca+[veccvecavecr]vecb+[vecavecbvecr]vecr=[vecavecbvecc]vecr`
2 Answers 1 viewsAs `veca ,vecb and vecc` are non- coplanar, `vecb xx veca,veccxxveca and vecaxxvecb` are also non-coplanar, So, any vector con be expressend as a linear combination of these vectors. `veca=lambdavecbxxvecc+mu...
2 Answers 1 viewsCorrect Answer - C `(c )` ` (a^(2)+b^(2))x^(2)-2b(a+c)x+b^(2)+c^(2)=0` `D=4b^(2)(a+c)^(2)-4(a^(2)+b^(2))(b^(2)+c^(2))` `=-4(b^(4)-2b^(2)ac+a^(2)c^(2))` `=-(n^(2)-ac)^(2)` For real roots, `D ge 0` `implies -4(b^(2)-ac)^(2) ge 0` `implies b^(2)-ac=0` `implies` Roots are real and equal. `:.` Roots...
2 Answers 1 viewsCorrect Answer - A `(a)` The other five letters (other than `G`, `R`, `L`, `A`, `S`, `N`) in `11` places can be arranged in `"^(11)P_(5)` ways. Then three remains six places....
2 Answers 1 viewsCorrect Answer - A `(a)` First arrange `12` persons `A_(4),A_(5),….A_(15)` in `"^(15)P_(12)` ways There remains `3` places. Keep `A_(1)` in the first place and arrange `A_(2)`, `A_(3)` in the remaining two...
2 Answers 1 viewsCorrect Answer - D `(d)` The given system of equations will have a non-trivial solution if `|{:(alpha+a,alpha,alpha),(alpha,alpha+b,alpha),(alpha,alpha,alpha+c):}|=0` Operate `R_(2)toR_(2)-R_(1)` , `R_(3)-R_(3)-R_(1)`, then `|{:(alpha+a,alpha,alpha),(-a,b,0),(-a,0,c):}|=0` `impliesalpha(bc+ca+ab)+abc=0` Since, `a,b,c ne 0` `:.(1)/(alpha)=-((1)/(a)+(1)/(b)+(1)/(c ))`
2 Answers 1 viewsi. Minimum four Directors Meetings must be held in a year. ii. Annual General Meeting must be held once a year. iii. Annual General Meeting must be held every year. iv. The Meeting of all Directors is...
2 Answers 1 viewsCorrect option is: (A) unit vector
2 Answers 1 views