The expression 1/√2 (i + j) is a
(A) unit vector
(B) null vector
(C) vector of magnitude √2
(D) scalar
Let `P=(AB^(T)-BA^(T))` `:. P^(T)=(AB^(T)-BA^(T))^(T)=(AB^(T))^(T)-(BA^(T))^(T)` `=(B^(T))^(T) (A)^(T)-(A^(T))^(T)B^(T)=BA^(T)-AB^(T)` `=-(AB^(T)-BA^(T))=-P` Hence, `(AB^(T)-BA^(T))` is a skew-symmetric matric.
2 Answers 1 viewsCorrect Answer - B `A=((a,0),(0,b))` `implies A^(2)=((a,0),(0,b))((a,0),(0,b))=((a^(2),0),(0,b^(2)))` `implies A^(3)=((a^(2),0),(0,b^(2))) ((a,0),(0,b))=((a^(3),0),(0,b^(3)))` `implies A^(n)=((a^(n),0),(0,b^(n)))` `implies (A^(n))^(-1) =1/(a^(n)b^(n)) ((b^(n),0),(0,a^(n)))=((a^(-n),0),(0,b^(-n)))` `implies lim_(n rarr oo) (A^(n))^(-1)=((0,0),(0,0))` as `a gt 1` and `b gt 1`
2 Answers 1 views`[E]=[ML^(2)T^(-2)]=(5)` `=(10)^(2)(5)^(2)=20` joules
2 Answers 2 viewsCorrect Answer - c Given that `vecV = 2hati +hatj -hatk and vecW =hati + 3hatk and vecU` is a unit vector ` |vecU|=1` Now `|vecU vecV vecW] = vecU.(vecV xx...
2 Answers 1 viewsCorrect Answer - `B=(1)/(2)mu_(0)j`
2 Answers 1 viewsCorrect answer is (A) zero
2 Answers 1 viewsCorrect answer is (D) √3/2
2 Answers 1 viewsNo. Scalars Vectors i. It has magnitude only It has magnitude as well as direction. ii. Scalars can be added or subtracted according to the rules of the algebra. Vectors are added or subtracted by the geometrical (graphical)...
2 Answers 1 viewsCorrect option is: (A) zero vector
2 Answers 1 viewsCorrect option is: (C) 26
2 Answers 2 views