A potential difference of 10 V is applied across a conductor of resistance `1 k Omega`. Find the number of electrons flowing through the conductor in 5 minutes.
1 Answers
Talk Doctor Online in Bissoy App
A capacitor is connected to a 36 V battery through a resistance of `20 Omega`. It is found that the potential difference across the capacitor rises to
The charge on the capacitor during charging is given by `Q=Q_(0)(1-e^(-t//2RC))`. Hence, the potential difference across the capacitor is `V=Q//C=Q_(0)//C(1-e^(-t//2RC))`. Here, at ` t=2 mu s`, the potential difference is...
2 Answers 1 views
Electrons originally at rest are accelerated through a potential difference of V volts. The applied potential differ- ence is measured using a voltmet
Correct Answer - `(Deltalambda)/(lambda) = (DeltaV)/(2V)`
2 Answers 1 views
If `omega` is any complex number such that `z omega=|z|^(2)` and `|z-barz|+|omega+baromega|=4`, then as `omega` varies, then the area bounded by the l
Correct Answer - B `(b)` `zomega=|z|^(2)` `implieszomega=zbarz` `impliesomega=barz` `:. |z-barz|+|z+barz|=4` `:. |x|+|y|=2` which is a square `:.` Area `=8`sq. units
2 Answers 2 views
If `alpha`, `beta`, `gamma in {1,omega,omega^(2)}` (where `omega` and `omega^(2)` are imaginery cube roots of unity), then number of triplets `(alpha,
Correct Answer - C `(c )` As `|(aalpha+bbeta+cgamma)/(a beta+bgamma+calpha)|=1` `implies` When `alpha`, `beta`, `gamma` are different, then number of triplet `(alpha,beta,gamma)=` permutation of `1`, `omega` and `omega^(2)=6` and when `alpha-beta=gamma`, number...
2 Answers 2 views
If `y_(1)=max||z-omega|-|z-omega^(2)||`, where `|z|=2` and `y_(2)=max||z-omega|-|z-omega^(2)||`, where `|z|=(1)/(2)` and `omega` and `omega^(2)` are c
Correct Answer - C `(c )` We have `||z_(1)|-|z_(2)|| le |z_(1)-z_(2)|` and equality holds only when `argz_(1)=argz_(2)` `implies||z-w|-|z-w^(2)|| le |w^(2)-w| le sqrt(3)` and equality canhold only when `|z|=2` and not when...
2 Answers 1 views
vii) A cell of emf \( 1.1 V \) and internal resistance \( r \) is connected across an external resistor of resistance \( R=10 \). The potential difference across the resistor is a) \( 0.1 V \) b) \( 0.9 V \) c) \( 1.0 V \) d) \( 1.1 V \)
Given E = 1.1 V r = r R = 10 r Potential difference across the resistor = IR = (E/R+r) R = (1.1/10r+r) 10 r \(=\frac{1.1\times10\,r}{11\,r\times10}\) = 11/11 = 1 volt option (c) is correct.
2 Answers 2 views
The resistance of two conductors in series is `18 Omega` and the resistance becomes `4 Omega` when connected in parallel. Find the resistance of indiv
Correct Answer - `12 Omega, 6 Omega`
2 Answers 1 views
A battery of emf 2 V and internal resistance `0.5 Omega` is connected across a resistance of `9.5 Omega`. How many electrons pass through a cross-sect
Correct Answer - `1.25xx10^(18)`
2 Answers 1 views
When a resistance of `2 Omega` is placed across the terminals of a battery, the current is 0.5 A. When the resistance across the terminals of the batt
Correct Answer - `1.5 V, 1 Omega`
2 Answers 1 views
A 20 V battery of internal resistance `1 Omega` is connected to three coils of `12 Omega, 6 Omega` and `4 Omega` in parallel, a resistor of `5Omega` a
Correct Answer - `1.2 A, 0.2 A, 0.4 A, 0.6 A, 18.8 V, 10.4 V`
2 Answers 1 views