The resistance of two conductors in series is `18 Omega` and the resistance becomes `4 Omega` when connected in parallel. Find the resistance of individual conductors.
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If `y_(1)=max||z-omega|-|z-omega^(2)||`, where `|z|=2` and `y_(2)=max||z-omega|-|z-omega^(2)||`, where `|z|=(1)/(2)` and `omega` and `omega^(2)` are c
Correct Answer - C `(c )` We have `||z_(1)|-|z_(2)|| le |z_(1)-z_(2)|` and equality holds only when `argz_(1)=argz_(2)` `implies||z-w|-|z-w^(2)|| le |w^(2)-w| le sqrt(3)` and equality canhold only when `|z|=2` and not when...
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Two batteries of emf 12V and 6V and internal resistance `2Omega` and `1Omega` are connected in parallel and the combination is connected to a resisor
Correct Answer - a) 8V, b) 6V, c)8V, 0.67 `Omega`
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A 150 V voltmeter has a resistance of 20,000`Omega` when connected in series with a large resistance R across a 110-volt line the meter reads 5V. Find
Correct Answer - `4.2xx10^(5)Omega`
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An ammeter and a voltmeter are connected in series to a battery of emf 6V. When a certain resistance is connected in parallel with the voltmeter, the
Correct Answer - `n:1,((E)/(n+1))=2V`
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Three resistors of `1 Omega, 2 Omega " and " 3 Omega` are combined in series. (i) What is the total resistance of the combination ? (ii) If the combin
Correct Answer - `(i) 6 Omega (ii) 2 V, 4 V, 6V`
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(i) Three resistors `2 Omega, 4 Omega " and " 5 Omega` are comined in parallel. What is the total resistance of the combination ? (ii) If the comnbina
Correct Answer - `(i) (20)/(19)Omega (ii) 10 A, 5 A, 4 A, 19 A`
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Two cells of emf of 1.5 V and 2.0 V having internal resistances of `1 Omega` and `2 Omega`, respectively are connected in parallel so as to send curre
Correct Answer - `(5)/(17)A`
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Three identical, each of emf 2 V and internal resistance `0.2 Omega` are connected in series to an external resistor of `7.4 Omega`. Calculate the cur
Correct Answer - `0.75 A`
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Three identical cells each of emf 2 V and unknown internal resistance are connected in parallel. This combination is connected to a `5 Omega` resistor
Correct Answer - `5 Omega`
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A 20 V battery of internal resistance `1 Omega` is connected to three coils of `12 Omega, 6 Omega` and `4 Omega` in parallel, a resistor of `5Omega` a
Correct Answer - `1.2 A, 0.2 A, 0.4 A, 0.6 A, 18.8 V, 10.4 V`
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