Correct Answer - C
The required probability is
1- probability of getting equal number of heads and tails
`=1-""^(2n)C_(n)((1)/(2))^(n)((1)/(2))^(2n-n)`
`=1-((2n)!)/((n!)^(2))xx(1)/(4^(n))`
Correct Answer - A
`(a)` At event `A` he gets a number greater than `3`
`:.P(A)=1//2`
At event `B` he gets `5` in last throw
`:.P(B)=1//6`
`:.` Required probability is
`P(E)=(1)/(6)+(1)/(2)*(1)/(6)+(1)/(2)*(1)/(2)*(1)/(6)+…..oo`...
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