In a head-on collision between and `alpha`-particle and a gold nucleus, the distance of closest approach is 4.13 fermi. Calculate the energy of the particle. (1 fermi `= 10^(-15) m`)
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An `alpha`-particle having kinetic energy x MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which `alpha`-particle reaches is
Correct Answer - 5 `K.E.=(KZe.2e)/(r ), " "K.E.=(9xx10^(9)xx29xx2(1.6 xx 10^(-19))^(2))/(1.67xx10^(-14))=5Mev`
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If `A(alpha, beta)=[("cos" alpha,sin alpha,0),(-sin alpha,cos alpha,0),(0,0,e^(beta))]`, then `A(alpha, beta)^(-1)` is equal to
Correct Answer - A We have, `A(alpha, beta)^(-1)=1/e^(beta) [(e^(beta) cos alpha,-e^(beta) sin alpha,0),(e^(beta) sin alpha,e^(beta) cos alpha,0),(0,0,1)]` `=A(-alpha, -beta)`
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(a) Why is an alpha particle, rather than neutrons and protons, emitted from an unstable nucleus? (b) A nucleus `.^(A)X` alpha decays to produce Y. Th
Correct Answer - (b) A=228
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There are two sets of parallel lines, their equations being `x cos alpha+y sin alpha=p` and `x sin alpha- y cos alpha=p` , `p=1,2,3,….n` and `alpha in
Correct Answer - C `(c )` `"^(n)C_(2)*^(n)C_(2)=225impliesn=6`
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An alpha particle of velocity `1.6xx10^(7) ms^(-1)` approaches a gold nucleus (Z=79). Calculate the distance of the closest approach. Mass of an alpha
Correct Answer - `4.3 xx 10^(-14)m` , the size of the nucleus cannot be greater than `4.3 xx 10^(-14)m`.
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An `alpha` particle of `K.E. 10^(-12)J` exhibits back scattering from a gold nucleus Z=79. What can be the maximum possible radius of the gold nucleus
Correct Answer - `3.64 xx 10^(-14)m`
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A protom of energy 1 MeV is incident head-on on a gold nucleus (Z = 79), and is scattered through an angle of `180^(@)`. Calculate the distance of nea
Correct Answer - `11.37 xx 10^(-4) m`
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In a head-on collision between an `alpha`-particle and a gold nucleus, the minimum distance of approach is `3.95 xx 10^(4)m`. Calculate the energy of
Correct Answer - 6 MeV
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What is the distance of closest approach to the nucleus for an `alpha`-particle of energy 5J MeV which undergoes scattering in the Gieger-Marsden expe
Correct Answer - `4.13 xx 10^(-14) m`
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A n `alpha`-particle of velocity `1.6xx10^(7) m s^(-1)` approaches a gold nucleii `(Z=79)`. Calculate the distance of closest approach. Mas of an `alp
Correct Answer - `4.3xx10^(-14) m`
2 Answers 1 views