The standard oxidation potential for the half-cell `NO_(2)^(-)(g)+H_(2)OtoNO_(3)^(-)(aq)+2H^(+)(aq)+2e` is `-0.78V`. Calculate the reduction in 9 mola

Monjur Alahi

The standard oxidation potential for the half-cell
`NO_(2)^(-)(g)+H_(2)OtoNO_(3)^(-)(aq)+2H^(+)(aq)+2e` is `-0.78V`.
Calculate the reduction in 9 molar `H^(+)` assuming all other species at unit concentration. What will be the reduction potential in neutral medium?


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Salim Ahmed Kawsar

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Correct Answer - `0.836"volt", 1.1937"volt"`
`E_("oxidation")=-0.78-(0.0591)/(2)log9^(2)=-0.78-(0.0591)/(2)xx2xxlog9=-0.835"volt"`
`E_("reduction")=-E_("oxidation")=0.836"volt"`
In neutral medium
`E_("Oxidation")=-0.78-(0.0591)/(2)log(10^(-7))^(2)=-1.1937"volt"`

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