A bag contains 3 red, 7 white, and 4 black balls.
If three balls are drawn from the bag, then find the probability that all of
them are of the same color.
Correct Answer - `(10)/(91)`
The required probability is
`(.^(3)C_(3) + .^(7)C_(3) + .^(4)C_(3))/(.^(14)C_(3)) = (1 + 35 + 4)/(14 xx 13 xx 2) = (40)/(14 xx 26) = (10)/(91)`
Here, `W_(1)` = {4 white balls} and `B_(1)`={5 black balls}
and `W_(2)` = {9white balls} and `B_(2)` = {7 black balls}
Let E, is the event that ball transferred fram...
Bag I ={3B,2W],Bag II={2B,4W}
Let `E_(1)`=Event that bag I is selected
`E_(2)`=Event that bag II is selected
and E=Event that a black ball is selected
`rArrP(E_(1))=1//2,P(E_(2))=1/2,P(E//E_(1))=3/5,P(E//E_(2))=2/6=1/3`
`thereforeP(E)=P(E_(1))cdotP(E//E_(1))+P(E_(2))cdotP(E//E_(2))`
`1/2cdot3/5+1/2cdot2/6=3/10+2/12`
`=(18+10)/60=28/60=7/15`
Let `U_(1)`={2 white, 3 black balls}
`U_(2)`={3 white , 2 black balls}
and `U_(3)`={4 white ,1 black balls}
`thereforeP(U_(1))=P(U_(2))=P(U_(3))=1/3`
Let `E_(1)` be the event that a ball is chosen from...
Correct Answer - A::B
Let the number of red and blue balls be r and b, respectively. Then, the probability of drawing two red balls is
`p_(1) = (.^(r )C_(2))/(.^(r+b)C_(2)) =...
Procedure of drawing th balls has to end at the rth draw. So, exactly two black balls are drawn in first (r-1) draws and third black ball is drawn in...
Correct Answer - `1//4`
If third ball is red, then in first two draws, there will be either no red ball or one red ball.
Let events
`R_(0)=` in first two...
Correct Answer - A
P (required)
= P (all are white) + P (all are red) + P (all are black)
`=1/6xx2/9xx3/12+3/6xx3/9xx4/12+2/6xx4/9xx2/12=6/648+36/648+40/648=82/648`