A bag contains 3 white and 2 black balls and another bag contains 2 white and 4 black balls. One bag is chosen at random. From teh selected bag, one b

Correct option is: A) \(\frac{3}{5}\) There are 6 red, 3 black and 6 white balls. \(\therefore\) Total number of balls = 6 + 3 + 6 = 15. Number of balls which are not red =...

Here, `W_(1)` = {4 white balls} and `B_(1)`={5 black balls} and `W_(2)` = {9white balls} and `B_(2)` = {7 black balls} Let E, is the event that ball transferred fram...

Bag I : 3 red balls and 0 white ball Bag II : 2 red balls and 1 white ball. Bag III : 0 red ball andf 3 white balls....

Since, Bag I= {3 black, 4 white balls}, Bag II = {4 black, 3 white balls} Let `E_(1)` be the event that bag is selected and `E_(2)` be the event...

Let `U_(1)`={2 white, 3 black balls} `U_(2)`={3 white , 2 black balls} and `U_(3)`={4 white ,1 black balls} `thereforeP(U_(1))=P(U_(2))=P(U_(3))=1/3` Let `E_(1)` be the event that a ball is chosen from...

Correct Answer - A::B Let the number of red and blue balls be r and b, respectively. Then, the probability of drawing two red balls is `p_(1) = (.^(r )C_(2))/(.^(r+b)C_(2)) =...

Procedure of drawing th balls has to end at the rth draw. So, exactly two black balls are drawn in first (r-1) draws and third black ball is drawn in...

Let `A_(i)` denote the event that the number I appears on the dice and let E denote the event that only white balls are drawn. Then `P(A_(i))=1/6"for"i=1,2..,6` `and P(E//A_(i))=(""^(6)C_(i))/(""^(10)C_(i)),i=,2,.., 6`...

Correct Answer - A Let `E_(i)` denote the event that the bag contains I blck and `(10-i)` white balls `(i=0,1,2,…,10).` Let A denote the event that the three balls drawn at...

Correct Answer - A P (required) = P (all are white) + P (all are red) + P (all are black) `=1/6xx2/9xx3/12+3/6xx3/9xx4/12+2/6xx4/9xx2/12=6/648+36/648+40/648=82/648`