Which of the following is/are correct for nuclear reactor? a)A typical fission is represented by `""_(92)""^(235)U=""_(0)""^(1)nto""_(54)""^(140)Ba+""

Monjur Alahi

Which of the following is/are correct for nuclear reactor? a)A typical fission is represented by
`""_(92)""^(235)U=""_(0)""^(1)nto""_(54)""^(140)Ba+""_(36)""^(93)Kr+` Energy b)Heavy water (`D""_(2)O`) is used as moderator in preference to orduinary water (`H""_(2)O`) because hydrogen may capture neutrons, while D would not do that c)Cadmium rods increse the reactor power when they go in and decrease when they go outwards d)Slower neutrons are more effective in causing fission than faster neutrons in the case of `""_(235)U`
A. A typical fission represented by `._(92)U^(235)+._(0)n^(1) rarr._(56)Ba^(143)+._(36)Kr^(93)+"energy"`
B. Heavy water is used as moderator in preference to ordinary water because H may capture neultrons. While D would not
C. Cadmium rod increase the reactor power when they go in, decrease when they go outward
D. Slower neutron are more effective in causing fission than faster neutrons in case of `U^(235)`


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

Correct Answer - A::B::D
A is balanced both in mass number & atomic no.

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to `2 : 1`. What will be the ratio of their nuclear size (nuclear rad

Correct Answer - D Applying conservation of momentum, we get `m_(1) v_(1) = m_(2) v_(2) rArr (m_(1))/(m_(2)) = (v_(2))/(v_(1)) = (1)/(2)` Also, `R prop m^(1//3) rArr m prop R^(3)` `(m_(1))/(m_(2)) =...

2 Answers 1 views
In a nuclear reactor, the number of `U^(235)` nuclei undergoing fissions per second is `4xx10^(20).` If the energy releases per fission is 250 MeV, th

Correct Answer - B (B) the fission per second `=4xx10^(20)` So , the energy relased per second `=4xx10^(20) xx250MeV ` `=4xx10^(20) xx250xx10^(6) xx1.6xx10^(-19) J` therefore , energy relased in 10 h`=...

2 Answers 1 views
The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

Correct Answer - A (a) Let there is n number of fission per second produces a power of 6.4 W, then `nxx200x10^(6) xx16x10^(-19) Js^(-1) =6.4Js^(-1)` `therefore n=(6.4)/( 200xx10^(-13) xx1.6)=(4)/(2xx10^(-11))=2xx10^(11)`

2 Answers 1 views
What is the energy released by fassion of 1 g of `U^(235)`? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

Correct Answer - A (a) Energy relased in one fission of `""_(92)^(235)U` nucleus `=200 meV ` Mass of uranium = 1 g we know that , 235 g of ` ""^(235)U`...

2 Answers 1 views
`A U^(235)` reactor generated power at a rate of P producting `2xx10^(18)` fussion per second. The energy released per fission is 185 MeV. The value o

Correct Answer - A Power, `P=(nE)/(t)` Given, `n=2xx10^(18)` fission per second E=185MeV Here, `P=(2xx10^(18)xx185xx10^(6)eV)/(1)` `implies=2xx10^(18)xx185xx10^(6)xx16xx10^(-19)=59.2MW`

2 Answers 1 views
`U^(235) + n^(1)rarr` fission product + neutron + 3.2`xx 10^(-11)j`. The energy released , when 1g of `u^(235)` finally undergoes fission , is

Correct Answer - C 235 g of u-235 contains `6.023xx10^(23)` atoms 1g u-235=`(6.023xx10^(23))/(235)atoms` `therefore` Energy relaeased =`(3.2xx10^(-11)xx6.023xx10^(23))/(235)j` `=8.21xx10^(10)j` `8.21xx10^(7) kj`

2 Answers 1 views
It is proposed to use the nuclear fusion reaction, `._1^2H+_1^2Hrarr_2^4He` in a nuclear reactor `200 MW` rating. If the energy from the above reactio

Energy released in the nuclear fusion is `Q = Deltamc^(2) = Deltam(931) MeV` (where `Deltam` is in amu) `Q = (2 xx 2.0141 - 4.0026) xx 931 MeV = 23.834...

2 Answers 1 views
Evaluate the following limit: `lim_(nto oo)(sum_(r=1)^(n) sqrt(r)sum_(r=1)^(h)1/(sqrt(r)))/(sum_(r=1)^(n)r)`

Correct Answer - `8/3` `lim_(n to oo) (sum_(r=1)^(n)sqrt(r) sum_(r=1)^(n)1/(sqrt(4)))/(sum_(r=1)^(n)r)` `:.` Limit `=lim_(nto oo) (1/n sum_(r=1)^(n)sqrt(4/n)(1/nsum_(r=1)^(n)sqrt(n/r)))/(1/n sum_(r=1)^(n)r/n)` `=(int_(0)^(1)sqrt(x)dxint_(0)^(1)(dx)/(sqrt(x)))/(int_(0)^(1)x dx) =8/3`

2 Answers 1 views
(a ) सूर्य के भीतर गहराई (deep within ) में 1 kg हाइड्रोजन के संलयन में मुक्त ऊर्जा तथा (b) विखंडन रिऐक्टर (fission reactor ) में 1 kg ` "" _ (92 ) ^(

Correct Answer - (a) नोट करें कि सूर्य के अभ्यंतर में चार `._(1)^(1)H` नाभकि मिलकर संलयन एक `._(2)^(4)He` नाभिक बनाते हैं तथा प्रति संलयन लगभग `26MeV` की ऊर्जा विमुक्त होती...

2 Answers 1 views
Moderator is used in a nuclear to slow down fast neutrons generated after a fission event in the reactor consider a fast neutron (mass `m_(n)`) moving

Correct Answer - `((M-m_(n))/(M+m_(n)))^(2)`

2 Answers 1 views
X