The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

Monjur Alahi

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is
A. `2xx10^(11)`
B. `10^(11)`
C. `10^(10)`
D. `2xx10^(10)`


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Salim Ahmed Kawsar

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Correct Answer - A
(a) Let there is n number of fission per second produces a power of 6.4 W, then
`nxx200x10^(6) xx16x10^(-19) Js^(-1) =6.4Js^(-1)`
`therefore n=(6.4)/( 200xx10^(-13) xx1.6)=(4)/(2xx10^(-11))=2xx10^(11)`

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