Login
Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

If the atomic masses of C and S are 12 and 32 respectively, then atom of S is how many times heavier than an atom of carbon ?

Monjur Alahi

If the atomic masses of C and S are 12 and 32 respectively, then atom of S is how many times heavier than an atom of carbon ?
A. two extra protons and two extra electrons
B. two extra prtions but no extra but no wxtra electrons
C. two extra neutrons and no extra electrons
D. two extra neutrons and two extra elecrrons


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

Correct Answer - c
For `""_(6)C^(12)`
Proton =6 electron = and neutron = 6 For `""_(6)C^(14)`

0 like 0 dislike
1 views
There are two isotopes of an element with atomic mass z. Heavier on has atomic mass z+2 and lighter one has z-1, then abundance of lighter one is

Correct Answer - A Let percent abundance of lighter isotope = x `:. (x(z-1)+(100-x)(z+2))/(100)=z` `xz-z+100z+200-xz-2x=100z` `-3x = -200` `x = (200)/(6) = 66.6` `:.` percent abundance of lighter isotopes = x

2 Answers 1 views
The bond between carbon atom 1 and carbon atom 2 in a compound `NequivC-CH=CH-CH_(3)` involved the hybrids as :

Correct Answer - C `Nequivoverset(1)C-overset(2)CH=overset(3)CH-overset(4)CH_(3)" the "C_(1)-C_(2)` bond involves `sp-sp^(2)` hybrids.

2 Answers 1 views
A mixture of carbon monoxide and carbon dioxide is found to have a density of 1.7g/lit at S.T.P. The mole fraction of carbon monoxide is

Correct Answer - A `M_("mix")=(dRT)/P_("mix")implies M_("mix")=(1.7xx0.0821xx273)/1=1.7xx22.4` gms `M_("mix")=X_(CO)xxM_(CO)+(1-X_(CO).M_(CO_2)=X_(CO)xx18+(1-X_(CO))xx44 implies X_(CO)=0.37`

2 Answers 1 views
the three stable isotopes of 9.051% , 0.27% and 9.22% the atomic masses of the three isotopes are 19.99 u , 20 .99 u and 21.99u respectively the avera

Correct Answer - a The mass of the isotopes are `19.99` u `20.99` u and `21.99` u. Their relative abundances are `90.51%,0.27 and 9.22%` `therefore` Average atomic mass of neon `m=(90.51xx19.99xx0.27xx20.99+9.22xx21.99)/((90.51+0.27+9.22))`...

2 Answers 1 views
Electrons are revolving around the nucleus in `n_(1^(th))` orbit of an atom, have atomic number `Z_1`, and in the `n_2` orbit of other atom, have atom

Correct Answer - A,B,D `L_1/L_2=(mv_1r_1)/(mv_2r_2)=(Z_1/n_1xxn_1^2/Z_1)/(Z_2/n_2xxn_2^2/Z_2)=n_1/n_2implies P_1/P_2(mv_1)/(mv_2)=(Z_1/n_1)/(Z_2/n_2)=(Z_1n_2)/(Z_2n_1)` `(f_1)/(f_2) =(v_1/(2pir_1))/(v_2/(2pir_2))=(Z_1/n_1xxZ_1/n_1^2)/(Z_2/n_2xxZ_2/n_2^2)=(Z_1/Z_2)^2.(n_2/n_1)^3implies (K.E._1)/(K.E._2)=(1/2mv_1^2)/(1/2mv_2^2)=(Z_1/Z_2)^2xx(n_2/n_1)^2=((Z_1n_2)/(Z_2n_1))^2` `(K.E_1)/(K.E_2)=(1/2(KZ_1e^2)/r_1)/(1/2(KZ_2e^2)/r_2)=(Z_1/n_1^2.Z_1)/(Z_2.Z_2/n_2^2)=(Z_1/Z_2.n_2/n_1)^2`

2 Answers 1 views
The noble gases heavier than air are

Correct Answer - A::D Out of the given four noble gases only Ar (At. Mass 39) and (Kr (At. Mass 84) are heavier than air. He (At. Mass 4) and Ne...

2 Answers 1 views
A die is thrown 7 times. What is the chance that an odd number turns up (i) exactly 4 times (ii) at least 4 times

Probability of success is 3/6=1/2. `thereforep=1/2andq=1/2` (i) For exactly 4 successes, the required probability is `""^(7)C_(4)((1)/(2))^(4)((1)/(2))^(3)=35/128` (ii) For at least 4 successes, the required probability is `""^(7)C_(4)((1)/(4))^(4)((1)/(2))^(3)+""^(7)C_(5)((1)/(2))^(5)((1)/(2))^(2)` `+""^(7)C_(6)((1)/(2))^(6)((1)/(2))^(1)+""^(7)C_(7)((1)/(2))^(7)` `=35/128+21/128+7/128+1/128=64/128=1/2`

2 Answers 1 views
A fair coin is tossed `n` times. if the probability that head occurs 6 times is equal to the probability that head occurs 8 times, then find the value

Correct Answer - `n=14` According to question `""^(n)C_(6)((1)/(2))^(6)((1)/(2))^(n-6)=""^(n)C_(8)((1)/(2))^(8)((1)/(2))^(n-8)` `or ""^(n)C_(6)((1)/(2))^(n)=""^(n)C_(8)((1)/(2))^(n)` `or""^(n)C_(6)=""^(n)C_(8)=""^(n)C_(n-8)` `implies6=n-8orn=14`

2 Answers 1 views
A die is thrown a fixed number of times. If probability of getting even number 3 times is same as the probability of getting even number 4 times, then

Correct Answer - D According to the givn condition, `""^(n)C_(3)((1)/(2))^(n)=""^(n)C_(4)((1)/(2))^(n),` where n is the number of times die is thrown. `therefore""^(n)C_(3)=""^(n)C_(4)impliesn=7` Thus, the required probability is `=""^(7)C_(1)((1)/(2))^(7)=(7)/(2^(7))=(7)/(128)`

2 Answers 1 views
A coin is tossed `2n` times. The chance that the number of times one gets head is not equal to the number of times one gets tails is `((2n !))/((n !)^

Correct Answer - C The required probability is 1- probability of getting equal number of heads and tails `=1-""^(2n)C_(n)((1)/(2))^(n)((1)/(2))^(2n-n)` `=1-((2n)!)/((n!)^(2))xx(1)/(4^(n))`

2 Answers 1 views

Log in to ask questions, provide answers, or leave comments.


Login

Install the Bissoy app to consult with a doctor.


Download