There are two isotopes of an element with atomic mass z. Heavier on has atomic mass z+2 and lighter one has z-1, then abundance of lighter one is
A. `66.6%`
B. `96.7%`
C. `6.67%`
D. `33.3%`
Correct Answer - A
Equivalent mass of A = `("Atomic mass")/("valency") = (112)/(x)`
Equivalent mass of B = `("Atomic mass")/("valency") = (27)/(3) = 9`
`("Mass of A")/("Mass of B") = ("Equivalent...
Correct Answer - B
`("At. Mass of silver on old scale")/("At. mass of" .^(16)O "on old scale")`
`=("At. Mass of silver on new scale")/("At. Mass of" .^(16)O "on new scale")`
`("At....
Correct Answer - C
We know Atomic mass= `(6.4)/("sp. Heat (in calories)")`
Also 4.184 J = `~~` 1 calorie
1J=0.239 cal `~~` 0.24 cal `g^(-1) k^(-1)`
Atomic mass =6.4/0.24 =26.77 `~~`27.0
Correct Answer - a
The mass of the isotopes are `19.99` u `20.99` u and `21.99` u.
Their relative abundances are `90.51%,0.27 and 9.22%`
`therefore` Average atomic mass of neon
`m=(90.51xx19.99xx0.27xx20.99+9.22xx21.99)/((90.51+0.27+9.22))`...
Correct Answer - A
The element which present just below the given element will have outermost electromic configuration as `4s^(2) 4p^(3),` so its full electronic configuration is `1s^(2),2s^(2),2p^(6),3s^(2)3p^(6),4s^(2), 3d^(10), 4p^(3)` and...