The ratio between acceleration of the electron in singly ionised helium atom and doubly ionised lithium atom (both in ground state ) is

Monjur Alahi

The ratio between acceleration of the electron in singly ionised helium atom and doubly ionised lithium atom (both in ground state ) is
A. `(4)/(9)`
B. `(27)/(8)`
C. `(8)/(27)`
D. `(9)/(4)`


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

Correct Answer - C
`a=(v^(2))/(r) or a prop ((Z)^(2))/((1//Z))`
`" " aprop Z^(3)`
For singly ionised helium atom, Z=2
and doubly ionised lithium atom Z=3
`rArr" " (a_(He))/(a_(Li))=((2)^(3))/((3)^(3))=(8)/(27)`

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
The energy of the electron in the ground state of hydrogen atom is `-13.6 eV`. Find the kinetic energy and potential energy of electron in this state.

Correct Answer - B Kinetic energy of electron in ground state =-(Totoal energy in this state) `" " --(13.6 )eV=13.6 eV`

2 Answers 1 views
The electron in a hydrogen atom makes a transition from M shell to L-shell. The ratio of magnitude of initial to final acceleration of the electron is

Correct Answer - D `a=omega^(2)r` As `" " omegaprop(1)/(n^(3))" " and " : r propn^(2)` `" "aprop(1)/(n^(4))` `rArr" " (a_(M))/(a_(L))=((2)/(3))^(4)=(16)/(81)`

2 Answers 1 views
In an inelastic collision an electron excites a hydrogen atom from its ground state to a M-Shell state. A second electron collides instantaneously wit

Correct Answer - D The ground state of hydrogen (n=1) is represented by K, the first excited state (n=2) is represented by L,the second excited state (n=3) is represent byb...

2 Answers 1 views
Assertion Energy `E_(1)` is required to remove first electron from helium atom and energy `E_(2)` is to required to remove the second electron . Them

Correct Answer - B `E_(H)=13.6eV` (inoisation energy ) `E_(He^(+))=13.6(Z)^(2)=(13.6)(Z)^(2)=54.4eV`

2 Answers 1 views
The electric current I created by the electron in the ground state of H atom bohr model in terms of bohr radius `(a_0)` and velocity of electron in fi

Correct Answer - A In the ground state of hydrogen atom, suppose, `a_0=` bohr radius `v_0=` velocity of electron in first orbit `therefore` time taken by electron to complete one revolution,...

2 Answers 1 views
The radius of electron orbit and the speed of electron in the ground state of hydrogen atom is `5.30xx10^(-11)m` and `22xx10^(6)m s^(-1)` respectively

Correct Answer - D Here, `r_1=5.30xx10^(-11)m,v_1=2.2xx10^6ms^(-1)` In the second excited state, `r_n=n^2r_1,v_n=(v_1)/(n)` `therefore r_2=4r_1=4xx5.30xx10^(-11)m=2.12xx10^(-10)m` and `v_2=(v_1)/(2)=(2.2xx10^(6))/(2)ms^(-1)=1.1xx10^(6)ms^(-1)`

2 Answers 2 views
An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy

Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.

2 Answers 1 views
For a doubly ionised Li-atom

Correct Answer - A::B::C::D (A) `L = (nh)/(2pi)` , (B) `E = (-13.6Z^(2))/(n^(2))` (C ) `v = (c )/(137)(Z)/(n)` , (D) `K = -(U)/(2)`

2 Answers 1 views
An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the r

Correct Answer - B `E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For second excited state to first excited state `E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))` For first excited state...

2 Answers 1 views
An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energ

Correct Answer - C Excitation upto `n=3` is required so that visible length is emitted upon de-excitation. So required energy `=13.6 (1-1/9)=12.1 eV`

2 Answers 1 views
X