Helium nuclei combines to form an oxygen nucleus. The energy released per nucleon of oxygen nucleus is if `m_(0)=15.834` amu and `m_(He)=4.0026 `amu
A. `10.24 MeV`
B. 0MeV
C. `5.24 MeV`
D. 4 MeV
Correct Answer - A
`4 ._(2)He^(4) rarr _(8)O^(16)`
Mass defect `=4 xx 4.0026 -15.834 a.m.u.=0.1764 a.m.u.`
Total energy released `=0.1764 xx 931 `MeV
Energy released /Nucleon`=(0.1764 xx 931)/(16)=10.24 `MeV
Correct Answer - A
Average speed `(r_(avg))=sqrt((8RT)/(piM))`
`(r_(He))/(r_(O_(2)))=sqrt(M_(O_(2))/(M_(He)))`
`(r_(He))/(r_(o_(2)))=sqrt32/4=2sqrt2`
`r_(He)=r_(o_(2))2sqrt2`
Correct Answer - `(xE_(0))/(2lambdaeL_(f))`
`overset(x)(rarr)Aoverset(lambda)(rarr)B`
No. of neuleus disintegrated `=xt-x/lambda (1-e^(-lambdat))`
for `t=1/lambda`
Distegration `=x/lambda [1-1+e^(-1)]=x/(e lambda)`
Energy released `=(E_(0)x)/(e lambda)`
Energy utilized for melting `=0.5xx(E_(0)x)/(e lambda)`
Mass of ice melted...
Correct Answer - B
In a nuclear reaction the energy remains conservest
`P + ._(3)^(7)Li rarr 2(._(2)^(4)He)`
energy of proton `+ 7(5.60) = 2(4 xx 7.06)`
`rArr` energy of `= 17.28...
Correct Answer - B
Since B.E./Nucleon of Reactants is high energy will be absorbed,
Net energy absorbed =(Bond energy of Reactant nucleus )-(Total bond energy of Product Nuclei)
` =(40 xx...
Correct Answer - B
(B) the fission per second `=4xx10^(20)`
So , the energy relased per second
`=4xx10^(20) xx250MeV `
`=4xx10^(20) xx250xx10^(6) xx1.6xx10^(-19) J`
therefore , energy relased in 10 h`=...
Correct Answer - D
The binding energy for `""_(1)H^(1)` is around zero and also not given in the question so we can igonor it
`Q=2(4xx7.06)-7xx(5.60)=(8xx7.06)-(7xx5.60)`
`=56.48-39.2=17.28MeV~=17.3 MeV`
